Y=x^2-5x 6 parabola 208786

Select all that apply the parabola has a minimum since a > 0, the parabola opens up

Y=x^2-5x 6 parabola- Finding the yintercept of a parabola can be tricky Although the yintercept is hidden, it does exist Use the equation of the function to find the y intercept y = 12 x 2 48 x 49 The yintercept has two parts the xvalue and the yvalue Note that the xvalue is always zero So, plug in zero for x and solve for y y = 12 (0) 2 48 (0) 49 (Replace x with 0) where ( h , k ) are the coordinates of the vertex and a is a constant for a parabola in standard form y = ax2 bx c xvertex = − b 2a y = x2 − 5x −6 is in standard form with a = 1,b = − 5,c = − 6 ⇒ xvertex = − −5 2 = 5 2 substitute this into the equation for ycoordinate ⇒ yvertex = (5 2)2 −5( 5 2) −6 = − 49 4 ⇒ vertex = ( 5 2, − 49 4)

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 Stack Exchange network consists of 178 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack Exchange2Calcular el área limitada por la parábola y2 = 4x y la recta y = x De x = o a x = 4, la parábola queda por encima de la recta 3Calcular el área limitada por las gráficas de las funciones 3y =x2 e y = −x2 4x En primer lugar representamos las parábolas

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